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1131421055502 = 23375096491241
BaseRepresentation
bin10000011101101101111…
…100110011101000001110
311000011101200022202210010
4100131231330303220032
5122014122242234002
62223433451454050
7144512445202233
oct20355574635016
94004350282703
101131421055502
113a6918765061
1216333a757326
13829006b17ca
143ca9254578a
151e66e22d46c
hex1076df33a0e

1131421055502 has 16 divisors (see below), whose sum is σ = 2324000006352. Its totient is φ = 366947369280.

The previous prime is 1131421055489. The next prime is 1131421055591. The reversal of 1131421055502 is 2055501241311.

It is a super-2 number, since 2×11314210555022 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1131421055502.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2548245399 + ... + 2548245842.

It is an arithmetic number, because the mean of its divisors is an integer number (145250000397).

Almost surely, 21131421055502 is an apocalyptic number.

1131421055502 is an abundant number, since it is smaller than the sum of its proper divisors (1192578950850).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131421055502 is a wasteful number, since it uses less digits than its factorization.

1131421055502 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5096491283.

The product of its (nonzero) digits is 6000, while the sum is 30.

Adding to 1131421055502 its reverse (2055501241311), we get a palindrome (3186922296813).

The spelling of 1131421055502 in words is "one trillion, one hundred thirty-one billion, four hundred twenty-one million, fifty-five thousand, five hundred two".

Divisors: 1 2 3 6 37 74 111 222 5096491241 10192982482 15289473723 30578947446 188570175917 377140351834 565710527751 1131421055502