Base | Representation |
---|---|
bin | 10101000100110001… |
… | …01111110110101011 |
3 | 1002012111220120101012 |
4 | 22202120233312223 |
5 | 141132432043201 |
6 | 5110413214135 |
7 | 550244140622 |
oct | 124230576653 |
9 | 32174816335 |
10 | 11314331051 |
11 | 4886710421 |
12 | 223919134b |
13 | 10b40a245a |
14 | 7949346b9 |
15 | 46347e5bb |
hex | 2a262fdab |
11314331051 has 16 divisors (see below), whose sum is σ = 12206051328. Its totient is φ = 10457013600.
The previous prime is 11314331027. The next prime is 11314331053. The reversal of 11314331051 is 15013341311.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11314331051 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11314331053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 459290 + ... + 483296.
It is an arithmetic number, because the mean of its divisors is an integer number (762878208).
Almost surely, 211314331051 is an apocalyptic number.
11314331051 is a deficient number, since it is larger than the sum of its proper divisors (891720277).
11314331051 is a wasteful number, since it uses less digits than its factorization.
11314331051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24722.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 11314331051 its reverse (15013341311), we get a palindrome (26327672362).
The spelling of 11314331051 in words is "eleven billion, three hundred fourteen million, three hundred thirty-one thousand, fifty-one".
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