11314343304233 has 4 divisors (see below), whose sum is σ = 11315384480400. Its totient is φ = 11313302128068.

The previous prime is 11314343304137. The next prime is 11314343304281. The reversal of 11314343304233 is 33240334341311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11314343304233 - 2¹⁰ = 11314343303209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11314343304193 and 11314343304202.

It is not an unprimeable number, because it can be changed into a prime (11314343304133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520571783 + ... + 520593516.

It is an arithmetic number, because the mean of its divisors is an integer number (2828846120100).

Almost surely, 2^{11314343304233} is an apocalyptic number.

It is an amenable number.

11314343304233 is a deficient number, since it is larger than the sum of its proper divisors (1041176167).

11314343304233 is a wasteful number, since it uses less digits than its factorization.

11314343304233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1041176166.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 11314343304233 its reverse (33240334341311), we get a palindrome (44554677645544).

The spelling of 11314343304233 in words is "eleven trillion, three hundred fourteen billion, three hundred forty-three million, three hundred four thousand, two hundred thirty-three".