Base | Representation |
---|---|
bin | 1010010010100101010111… |
… | …0000100000110011100001 |
3 | 1111001122101210001102201010 |
4 | 2210221111300200303201 |
5 | 2440333323423411210 |
6 | 40021431114331133 |
7 | 2245302643416045 |
oct | 244512560406341 |
9 | 44048353042633 |
10 | 11314382638305 |
11 | 367244804124a |
12 | 1328977a29aa9 |
13 | 640c31c04816 |
14 | 2b1894916025 |
15 | 1494a6880920 |
hex | a4a55c20ce1 |
11314382638305 has 64 divisors (see below), whose sum is σ = 18692560592640. Its totient is φ = 5840400900096.
The previous prime is 11314382638303. The next prime is 11314382638313. The reversal of 11314382638305 is 50383628341311.
It is not a de Polignac number, because 11314382638305 - 21 = 11314382638303 is a prime.
It is a super-2 number, since 2×113143826383052 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11314382638303) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 335035461 + ... + 335069229.
It is an arithmetic number, because the mean of its divisors is an integer number (292071259260).
Almost surely, 211314382638305 is an apocalyptic number.
11314382638305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11314382638305 is a deficient number, since it is larger than the sum of its proper divisors (7378177954335).
11314382638305 is a wasteful number, since it uses less digits than its factorization.
11314382638305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38530.
The product of its (nonzero) digits is 1244160, while the sum is 48.
The spelling of 11314382638305 in words is "eleven trillion, three hundred fourteen billion, three hundred eighty-two million, six hundred thirty-eight thousand, three hundred five".
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