Base | Representation |
---|---|
bin | 10101000100110010… |
… | …11000001001110001 |
3 | 1002012112012221210121 |
4 | 22202121120021301 |
5 | 141133002333423 |
6 | 5110420530241 |
7 | 550245426064 |
oct | 124231301161 |
9 | 32175187717 |
10 | 11314496113 |
11 | 4886813438 |
12 | 2239250981 |
13 | 10b412c61b |
14 | 7949788db |
15 | 4634b345d |
hex | 2a2658271 |
11314496113 has 2 divisors, whose sum is σ = 11314496114. Its totient is φ = 11314496112.
The previous prime is 11314496107. The next prime is 11314496147. The reversal of 11314496113 is 31169441311.
It is an a-pointer prime, because the next prime (11314496147) can be obtained adding 11314496113 to its sum of digits (34).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7374172129 + 3940323984 = 85873^2 + 62772^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314496113 - 29 = 11314495601 is a prime.
It is not a weakly prime, because it can be changed into another prime (11314496813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657248056 + 5657248057.
It is an arithmetic number, because the mean of its divisors is an integer number (5657248057).
Almost surely, 211314496113 is an apocalyptic number.
It is an amenable number.
11314496113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314496113 is an equidigital number, since it uses as much as digits as its factorization.
11314496113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7776, while the sum is 34.
The spelling of 11314496113 in words is "eleven billion, three hundred fourteen million, four hundred ninety-six thousand, one hundred thirteen".
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