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11315115131 = 49123045041
BaseRepresentation
bin10101000100110111…
…01111010001111011
31002012120101101221012
422202123233101323
5141133132141011
65110442104135
7550253614565
oct124233572173
932176341835
1011315115131
1148870a6521
1222394ab04b
1310b42b82c8
14794a9a335
15463586a8b
hex2a26ef47b

11315115131 has 4 divisors (see below), whose sum is σ = 11338160664. Its totient is φ = 11292069600.

The previous prime is 11315115113. The next prime is 11315115169. The reversal of 11315115131 is 13151151311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13151151311 = 75717372723.

It is a cyclic number.

It is not a de Polignac number, because 11315115131 - 26 = 11315115067 is a prime.

It is a super-2 number, since 2×113151151312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11315115097 and 11315115106.

It is not an unprimeable number, because it can be changed into a prime (11315115101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11522030 + ... + 11523011.

It is an arithmetic number, because the mean of its divisors is an integer number (2834540166).

Almost surely, 211315115131 is an apocalyptic number.

11315115131 is a deficient number, since it is larger than the sum of its proper divisors (23045533).

11315115131 is an equidigital number, since it uses as much as digits as its factorization.

11315115131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23045532.

The product of its digits is 225, while the sum is 23.

Adding to 11315115131 its reverse (13151151311), we get a palindrome (24466266442).

The spelling of 11315115131 in words is "eleven billion, three hundred fifteen million, one hundred fifteen thousand, one hundred thirty-one".

Divisors: 1 491 23045041 11315115131