Base | Representation |
---|---|
bin | 101011001010… |
… | …100000000111 |
3 | 210021212112202 |
4 | 223022200013 |
5 | 10344041312 |
6 | 1042305115 |
7 | 165114641 |
oct | 53124007 |
9 | 23255482 |
10 | 11315207 |
11 | 6429312 |
12 | 395819b |
13 | 24623b7 |
14 | 1707891 |
15 | ed79c2 |
hex | aca807 |
11315207 has 2 divisors, whose sum is σ = 11315208. Its totient is φ = 11315206.
The previous prime is 11315201. The next prime is 11315231. The reversal of 11315207 is 70251311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11315207 - 214 = 11298823 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11315201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657603 + 5657604.
It is an arithmetic number, because the mean of its divisors is an integer number (5657604).
Almost surely, 211315207 is an apocalyptic number.
11315207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11315207 is an equidigital number, since it uses as much as digits as its factorization.
11315207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 210, while the sum is 20.
The square root of 11315207 is about 3363.8084071481. The cubic root of 11315207 is about 224.5023205664.
Adding to 11315207 its reverse (70251311), we get a palindrome (81566518).
The spelling of 11315207 in words is "eleven million, three hundred fifteen thousand, two hundred seven".
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