Base | Representation |
---|---|
bin | 11001101110100101001000… |
… | …001011100011001011011111 |
3 | 112211122020102002201021212020 |
4 | 121232211020023203023133 |
5 | 104312341022321302401 |
6 | 1040353211321111223 |
7 | 32555654061036141 |
oct | 3156451013431337 |
9 | 484566362637766 |
10 | 113152124400351 |
11 | 33065601399493 |
12 | 10835781628513 |
13 | 4b1a27953292a |
14 | 1dd28407c6c91 |
15 | d1352e2bcd36 |
hex | 66e9482e32df |
113152124400351 has 8 divisors (see below), whose sum is σ = 151140360063024. Its totient is φ = 75299319168960.
The previous prime is 113152124400317. The next prime is 113152124400389. The reversal of 113152124400351 is 153004421251311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113152124400351 - 27 = 113152124400223 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113152124400391) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33857605870 + ... + 33857609211.
It is an arithmetic number, because the mean of its divisors is an integer number (18892545007878).
Almost surely, 2113152124400351 is an apocalyptic number.
113152124400351 is a deficient number, since it is larger than the sum of its proper divisors (37988235662673).
113152124400351 is an equidigital number, since it uses as much as digits as its factorization.
113152124400351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67715215641.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 113152124400351 its reverse (153004421251311), we get a palindrome (266156545651662).
The spelling of 113152124400351 in words is "one hundred thirteen trillion, one hundred fifty-two billion, one hundred twenty-four million, four hundred thousand, three hundred fifty-one".
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