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11315223342142 = 283248119274723
BaseRepresentation
bin1010010010101000011111…
…0111100010110000111110
31111001201120100222121120021
42210222013313202300332
52440342034133422032
640022050345442354
72245332532321456
oct244520767426076
944051510877507
1011315223342142
113672839653505
121328b714a03ba
13641037139705
142b1934438d66
15149505598097
hexa4a87de2c3e

11315223342142 has 16 divisors (see below), whose sum is σ = 17177458757760. Its totient is φ = 5589404802072.

The previous prime is 11315223342107. The next prime is 11315223342149. The reversal of 11315223342142 is 24124332251311.

It is a junction number, because it is equal to n+sod(n) for n = 11315223342098 and 11315223342107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11315223342149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41050393 + ... + 41325115.

It is an arithmetic number, because the mean of its divisors is an integer number (1073591172360).

Almost surely, 211315223342142 is an apocalyptic number.

11315223342142 is a deficient number, since it is larger than the sum of its proper divisors (5862235415618).

11315223342142 is a wasteful number, since it uses less digits than its factorization.

11315223342142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 522927.

The product of its digits is 34560, while the sum is 34.

Adding to 11315223342142 its reverse (24124332251311), we get a palindrome (35439555593453).

The spelling of 11315223342142 in words is "eleven trillion, three hundred fifteen billion, two hundred twenty-three million, three hundred forty-two thousand, one hundred forty-two".

Divisors: 1 2 83 166 248119 274723 496238 549446 20593877 22802009 41187754 45604018 68163996037 136327992074 5657611671071 11315223342142