Base | Representation |
---|---|
bin | 10101000100111000… |
… | …10001001100010101 |
3 | 1002012120122110110212 |
4 | 22202130101030111 |
5 | 141133201112122 |
6 | 5110445055205 |
7 | 550255033553 |
oct | 124234211425 |
9 | 32176573425 |
10 | 11315254037 |
11 | 488719091a |
12 | 2239557505 |
13 | 10b43365b9 |
14 | 794ad4bd3 |
15 | 4635b2ce2 |
hex | 2a2711315 |
11315254037 has 2 divisors, whose sum is σ = 11315254038. Its totient is φ = 11315254036.
The previous prime is 11315254003. The next prime is 11315254057. The reversal of 11315254037 is 73045251311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6020363281 + 5294890756 = 77591^2 + 72766^2 .
It is a cyclic number.
It is not a de Polignac number, because 11315254037 - 26 = 11315253973 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11315253994 and 11315254012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11315254057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657627018 + 5657627019.
It is an arithmetic number, because the mean of its divisors is an integer number (5657627019).
Almost surely, 211315254037 is an apocalyptic number.
It is an amenable number.
11315254037 is a deficient number, since it is larger than the sum of its proper divisors (1).
11315254037 is an equidigital number, since it uses as much as digits as its factorization.
11315254037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12600, while the sum is 32.
The spelling of 11315254037 in words is "eleven billion, three hundred fifteen million, two hundred fifty-four thousand, thirty-seven".
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