Base | Representation |
---|---|
bin | 10101000100111001… |
… | …00001100100111001 |
3 | 1002012120202212112100 |
4 | 22202130201210321 |
5 | 141133210234040 |
6 | 5110450334013 |
7 | 550255433322 |
oct | 124234414471 |
9 | 32176685470 |
10 | 11315321145 |
11 | 4887227287 |
12 | 223958a309 |
13 | 10b435accb |
14 | 794b11449 |
15 | 4635c7b30 |
hex | 2a2721939 |
11315321145 has 24 divisors (see below), whose sum is σ = 19756396296. Its totient is φ = 5990784768.
The previous prime is 11315321137. The next prime is 11315321177. The reversal of 11315321145 is 54112351311.
11315321145 is a `hidden beast` number, since 1 + 13 + 1 + 532 + 114 + 5 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 774397584 + 10540923561 = 27828^2 + 102669^2 .
It is not a de Polignac number, because 11315321145 - 23 = 11315321137 is a prime.
It is a super-2 number, since 2×113153211452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 911542 + ... + 923871.
It is an arithmetic number, because the mean of its divisors is an integer number (823183179).
Almost surely, 211315321145 is an apocalyptic number.
11315321145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11315321145 is a deficient number, since it is larger than the sum of its proper divisors (8441075151).
11315321145 is a wasteful number, since it uses less digits than its factorization.
11315321145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1835561 (or 1835558 counting only the distinct ones).
The product of its digits is 1800, while the sum is 27.
Adding to 11315321145 its reverse (54112351311), we get a palindrome (65427672456).
The spelling of 11315321145 in words is "eleven billion, three hundred fifteen million, three hundred twenty-one thousand, one hundred forty-five".
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