Base | Representation |
---|---|
bin | 11001101110100111001111… |
… | …111001000100001011010111 |
3 | 112211122110021210000112211211 |
4 | 121232213033321010023113 |
5 | 104312410203210144101 |
6 | 1040354225254042251 |
7 | 32556064356014533 |
oct | 3156471771041327 |
9 | 484573253015754 |
10 | 113154401256151 |
11 | 3306656a6419a2 |
12 | 108360b8049387 |
13 | 4b1a550163498 |
14 | 1dd29b8d4cbc3 |
15 | d1361411bc51 |
hex | 66e9cfe442d7 |
113154401256151 has 2 divisors, whose sum is σ = 113154401256152. Its totient is φ = 113154401256150.
The previous prime is 113154401256101. The next prime is 113154401256179. The reversal of 113154401256151 is 151652104451311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113154401256151 - 29 = 113154401255639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113154401256101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56577200628075 + 56577200628076.
It is an arithmetic number, because the mean of its divisors is an integer number (56577200628076).
Almost surely, 2113154401256151 is an apocalyptic number.
113154401256151 is a deficient number, since it is larger than the sum of its proper divisors (1).
113154401256151 is an equidigital number, since it uses as much as digits as its factorization.
113154401256151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 40.
The spelling of 113154401256151 in words is "one hundred thirteen trillion, one hundred fifty-four billion, four hundred one million, two hundred fifty-six thousand, one hundred fifty-one".
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