Base | Representation |
---|---|
bin | 10000011101111000111… |
… | …001001100001000100001 |
3 | 11000011212110210200020111 |
4 | 100131320321030020201 |
5 | 122020011243003143 |
6 | 2223504011011321 |
7 | 144520134606511 |
oct | 20357071141041 |
9 | 4004773720214 |
10 | 1131604656673 |
11 | 3a6a02367367 |
12 | 163390139b41 |
13 | 8292c74685a |
14 | 3caaca99841 |
15 | 1e6803e899d |
hex | 10778e4c221 |
1131604656673 has 2 divisors, whose sum is σ = 1131604656674. Its totient is φ = 1131604656672.
The previous prime is 1131604656619. The next prime is 1131604656703. The reversal of 1131604656673 is 3766564061311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 686332716304 + 445271940369 = 828452^2 + 667287^2 .
It is an emirp because it is prime and its reverse (3766564061311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131604656673 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131604656173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565802328336 + 565802328337.
It is an arithmetic number, because the mean of its divisors is an integer number (565802328337).
Almost surely, 21131604656673 is an apocalyptic number.
It is an amenable number.
1131604656673 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131604656673 is an equidigital number, since it uses as much as digits as its factorization.
1131604656673 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 1131604656673 in words is "one trillion, one hundred thirty-one billion, six hundred four million, six hundred fifty-six thousand, six hundred seventy-three".
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