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1131640400247 = 37509105869623
BaseRepresentation
bin10000011101111011000…
…001100010100101110111
311000011221222001122012120
4100131323001202211313
5122020044420301442
62223511325051023
7144521050456260
oct20357301424567
94004858048176
101131640400247
113a6a20560005
121633a00b6a73
1382936c7cbb6
143cab3721967
151e6836094ec
hex1077b062977

1131640400247 has 16 divisors (see below), whose sum is σ = 1727792263680. Its totient is φ = 645381215712.

The previous prime is 1131640400201. The next prime is 1131640400279. The reversal of 1131640400247 is 7420040461311.

It is not a de Polignac number, because 1131640400247 - 28 = 1131640399991 is a prime.

It is a super-2 number, since 2×11316404002472 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131640200247) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52924123 + ... + 52945500.

It is an arithmetic number, because the mean of its divisors is an integer number (107987016480).

Almost surely, 21131640400247 is an apocalyptic number.

1131640400247 is a deficient number, since it is larger than the sum of its proper divisors (596151863433).

1131640400247 is a wasteful number, since it uses less digits than its factorization.

1131640400247 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105870142.

The product of its (nonzero) digits is 16128, while the sum is 33.

Adding to 1131640400247 its reverse (7420040461311), we get a palindrome (8551680861558).

The spelling of 1131640400247 in words is "one trillion, one hundred thirty-one billion, six hundred forty million, four hundred thousand, two hundred forty-seven".

Divisors: 1 3 7 21 509 1527 3563 10689 105869623 317608869 741087361 2223262083 53887638107 161662914321 377213466749 1131640400247