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113167448242313 is a prime number
BaseRepresentation
bin11001101110110011011001…
…100011010111100010001001
3112211200200222001020010012112
4121232303121203113202021
5104313113413222223223
61040404224044152105
732560035602405213
oct3156633143274211
9484620861203175
10113167448242313
1133071055299793
1210838739538635
134b1b84c1a683a
141dd3495a295b3
15d13b29750778
hex66ecd98d7889

113167448242313 has 2 divisors, whose sum is σ = 113167448242314. Its totient is φ = 113167448242312.

The previous prime is 113167448242279. The next prime is 113167448242349. The reversal of 113167448242313 is 313242844761311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73430965840969 + 39736482401344 = 8569187^2 + 6303688^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113167448242313 is a prime.

It is not a weakly prime, because it can be changed into another prime (113167448242393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56583724121156 + 56583724121157.

It is an arithmetic number, because the mean of its divisors is an integer number (56583724121157).

Almost surely, 2113167448242313 is an apocalyptic number.

It is an amenable number.

113167448242313 is a deficient number, since it is larger than the sum of its proper divisors (1).

113167448242313 is an equidigital number, since it uses as much as digits as its factorization.

113167448242313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2322432, while the sum is 50.

The spelling of 113167448242313 in words is "one hundred thirteen trillion, one hundred sixty-seven billion, four hundred forty-eight million, two hundred forty-two thousand, three hundred thirteen".