11317433 has 4 divisors (see below), whose sum is σ = 11400180. Its totient is φ = 11234688.

The previous prime is 11317429. The next prime is 11317441. The reversal of 11317433 is 33471311.

11317433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33471311 = 3637 ⋅9203.

It can be written as a sum of positive squares in 2 ways, for example, as 3268864 + 8048569 = 1808^2 + 2837^2 .

It is a cyclic number.

It is not a de Polignac number, because 11317433 - 2² = 11317429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11317399 and 11317408.

It is not an unprimeable number, because it can be changed into a prime (11310433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41168 + ... + 41441.

It is an arithmetic number, because the mean of its divisors is an integer number (2850045).

Almost surely, 2^11317433 is an apocalyptic number.

It is an amenable number.

11317433 is a deficient number, since it is larger than the sum of its proper divisors (82747).

11317433 is an equidigital number, since it uses as much as digits as its factorization.

11317433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82746.

The product of its digits is 756, while the sum is 23.

The square root of 11317433 is about 3364.1392658450. The cubic root of 11317433 is about 224.5170414459.

Adding to 11317433 its reverse (33471311), we get a palindrome (44788744).

The spelling of 11317433 in words is "eleven million, three hundred seventeen thousand, four hundred thirty-three".