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113200023113 = 176658824889
BaseRepresentation
bin110100101101100111…
…1110100011001001001
3101211012002210222211122
41221123033310121021
53323313201214423
6124000421205025
711115126214622
oct1513317643111
9354162728748
10113200023113
114400a509911
1219b32560775
13a8a04760c8
14569c1b6a49
152e27eec8c8
hex1a5b3f4649

113200023113 has 4 divisors (see below), whose sum is σ = 119858848020. Its totient is φ = 106541198208.

The previous prime is 113200023109. The next prime is 113200023127. The reversal of 113200023113 is 311320002311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311320002311 = 499916227521.

It can be written as a sum of positive squares in 2 ways, for example, as 94527347209 + 18672675904 = 307453^2 + 136648^2 .

It is a cyclic number.

It is not a de Polignac number, because 113200023113 - 22 = 113200023109 is a prime.

It is a super-3 number, since 3×1132000231133 (a number of 34 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 6658824889 = 113200023113 / (1 + 1 + 3 + 2 + 0 + 0 + 0 + 2 + 3 + 1 + 1 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113200023091 and 113200023100.

It is not an unprimeable number, because it can be changed into a prime (113200023103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3329412428 + ... + 3329412461.

It is an arithmetic number, because the mean of its divisors is an integer number (29964712005).

Almost surely, 2113200023113 is an apocalyptic number.

It is an amenable number.

113200023113 is a deficient number, since it is larger than the sum of its proper divisors (6658824907).

113200023113 is an equidigital number, since it uses as much as digits as its factorization.

113200023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6658824906.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 113200023113 its reverse (311320002311), we get a palindrome (424520025424).

It can be divided in two parts, 11320002311 and 3, that multiplied together give a palindrome (33960006933).

The spelling of 113200023113 in words is "one hundred thirteen billion, two hundred million, twenty-three thousand, one hundred thirteen".

Divisors: 1 17 6658824889 113200023113