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1132000332131 = 1959578964849
BaseRepresentation
bin10000011110010000011…
…110100100100101100011
311000012220001100001221002
4100132100132210211203
5122021314041112011
62224011143422215
7144533011030334
oct20362036444543
94005801301832
101132000332131
113a7095749179
1216348075496b
1382993702946
143cb0945628b
151e6a5005c3b
hex107907a4963

1132000332131 has 4 divisors (see below), whose sum is σ = 1191579297000. Its totient is φ = 1072421367264.

The previous prime is 1132000332107. The next prime is 1132000332137. The reversal of 1132000332131 is 1312330002311.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1132000332131 - 230 = 1130926590307 is a prime.

It is a super-2 number, since 2×11320003321312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1132000332137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29789482406 + ... + 29789482443.

It is an arithmetic number, because the mean of its divisors is an integer number (297894824250).

Almost surely, 21132000332131 is an apocalyptic number.

1132000332131 is a deficient number, since it is larger than the sum of its proper divisors (59578964869).

1132000332131 is an equidigital number, since it uses as much as digits as its factorization.

1132000332131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59578964868.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1132000332131 its reverse (1312330002311), we get a palindrome (2444330334442).

The spelling of 1132000332131 in words is "one trillion, one hundred thirty-two billion, three hundred thirty-two thousand, one hundred thirty-one".

Divisors: 1 19 59578964849 1132000332131