Base | Representation |
---|---|
bin | 10000011110010000100… |
… | …101011011110010110011 |
3 | 11000012220011201110200102 |
4 | 100132100211123302303 |
5 | 122021320021143443 |
6 | 2224011250143015 |
7 | 144533032232243 |
oct | 20362045336263 |
9 | 4005804643612 |
10 | 1132002131123 |
11 | 3a7096767846 |
12 | 163481281a6b |
13 | 82993bb2736 |
14 | 3cb097a3b23 |
15 | 1e6a525dcb8 |
hex | 1079095bcb3 |
1132002131123 has 2 divisors, whose sum is σ = 1132002131124. Its totient is φ = 1132002131122.
The previous prime is 1132002131107. The next prime is 1132002131129. The reversal of 1132002131123 is 3211312002311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1132002131123 - 24 = 1132002131107 is a prime.
It is a super-2 number, since 2×11320021311232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1132002131095 and 1132002131104.
It is not a weakly prime, because it can be changed into another prime (1132002131129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566001065561 + 566001065562.
It is an arithmetic number, because the mean of its divisors is an integer number (566001065562).
Almost surely, 21132002131123 is an apocalyptic number.
1132002131123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132002131123 is an equidigital number, since it uses as much as digits as its factorization.
1132002131123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1132002131123 its reverse (3211312002311), we get a palindrome (4343314133434).
The spelling of 1132002131123 in words is "one trillion, one hundred thirty-two billion, two million, one hundred thirty-one thousand, one hundred twenty-three".
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