1132003103131 has 4 divisors (see below), whose sum is σ = 1162597781632. Its totient is φ = 1101408424632.

The previous prime is 1132003103089. The next prime is 1132003103137. The reversal of 1132003103131 is 1313013002311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1132003103131 - 2⁷ = 1132003103003 is a prime.

It is a super-2 number, since 2×1132003103131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1132003103099 and 1132003103108.

It is not an unprimeable number, because it can be changed into a prime (1132003103137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15297339195 + ... + 15297339268.

It is an arithmetic number, because the mean of its divisors is an integer number (290649445408).

Almost surely, 2^{1132003103131} is an apocalyptic number.

1132003103131 is a deficient number, since it is larger than the sum of its proper divisors (30594678501).

1132003103131 is an equidigital number, since it uses as much as digits as its factorization.

1132003103131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30594678500.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1132003103131 its reverse (1313013002311), we get a palindrome (2445016105442).

The spelling of 1132003103131 in words is "one trillion, one hundred thirty-two billion, three million, one hundred three thousand, one hundred thirty-one".