Base | Representation |
---|---|
bin | 110100101101101000… |
… | …0111100111001110001 |
3 | 101211012010101002020122 |
4 | 1221123100330321301 |
5 | 3323313240220423 |
6 | 124000431420025 |
7 | 11115131562536 |
oct | 1513320747161 |
9 | 354163332218 |
10 | 113200320113 |
11 | 4400a6a1a71 |
12 | 19b32684615 |
13 | a8a054b34a |
14 | 569c252d8d |
15 | 2e2805a8c8 |
hex | 1a5b43ce71 |
113200320113 has 2 divisors, whose sum is σ = 113200320114. Its totient is φ = 113200320112.
The previous prime is 113200320091. The next prime is 113200320169. The reversal of 113200320113 is 311023002311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75304689889 + 37895630224 = 274417^2 + 194668^2 .
It is a cyclic number.
It is not a de Polignac number, because 113200320113 - 232 = 108905352817 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113200320091 and 113200320100.
It is not a weakly prime, because it can be changed into another prime (113200323113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600160056 + 56600160057.
It is an arithmetic number, because the mean of its divisors is an integer number (56600160057).
Almost surely, 2113200320113 is an apocalyptic number.
It is an amenable number.
113200320113 is a deficient number, since it is larger than the sum of its proper divisors (1).
113200320113 is an equidigital number, since it uses as much as digits as its factorization.
113200320113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 113200320113 its reverse (311023002311), we get a palindrome (424223322424).
The spelling of 113200320113 in words is "one hundred thirteen billion, two hundred million, three hundred twenty thousand, one hundred thirteen".
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