Base | Representation |
---|---|
bin | 1010010010111010101100… |
… | …1101101010010111010101 |
3 | 1111002012012000120010022201 |
4 | 2210232223031222113111 |
5 | 2440432041443412133 |
6 | 40024215355524501 |
7 | 2245564624342462 |
oct | 244565315522725 |
9 | 44065160503281 |
10 | 11320111310293 |
11 | 36749177a1305 |
12 | 1329ab6459731 |
13 | 641635a01166 |
14 | 2b1c79696669 |
15 | 1496de76ed7d |
hex | a4bab36a5d5 |
11320111310293 has 2 divisors, whose sum is σ = 11320111310294. Its totient is φ = 11320111310292.
The previous prime is 11320111310279. The next prime is 11320111310359. The reversal of 11320111310293 is 39201311102311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5902654893444 + 5417456416849 = 2429538^2 + 2327543^2 .
It is a cyclic number.
It is not a de Polignac number, because 11320111310293 - 221 = 11320109213141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11320111310203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660055655146 + 5660055655147.
It is an arithmetic number, because the mean of its divisors is an integer number (5660055655147).
Almost surely, 211320111310293 is an apocalyptic number.
It is an amenable number.
11320111310293 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320111310293 is an equidigital number, since it uses as much as digits as its factorization.
11320111310293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 11320111310293 in words is "eleven trillion, three hundred twenty billion, one hundred eleven million, three hundred ten thousand, two hundred ninety-three".
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