11320120033 has 2 divisors, whose sum is σ = 11320120034. Its totient is φ = 11320120032.

The previous prime is 11320120003. The next prime is 11320120039. The reversal of 11320120033 is 33002102311.

11320120033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10203424144 + 1116695889 = 101012^2 + 33417^2 .

It is a cyclic number.

It is not a de Polignac number, because 11320120033 - 2¹³ = 11320111841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11320119989 and 11320120016.

It is not a weakly prime, because it can be changed into another prime (11320120039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660060016 + 5660060017.

It is an arithmetic number, because the mean of its divisors is an integer number (5660060017).

Almost surely, 2^11320120033 is an apocalyptic number.

It is an amenable number.

11320120033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320120033 is an equidigital number, since it uses as much as digits as its factorization.

11320120033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 11320120033 its reverse (33002102311), we get a palindrome (44322222344).

The spelling of 11320120033 in words is "eleven billion, three hundred twenty million, one hundred twenty thousand, thirty-three".