Base | Representation |
---|---|
bin | 10000011110010001001… |
… | …110111001110111100101 |
3 | 11000012220221011210000101 |
4 | 100132101032321313211 |
5 | 122021330312032323 |
6 | 2224012315144101 |
7 | 144533223520342 |
oct | 20362116716745 |
9 | 4005827153011 |
10 | 1132013002213 |
11 | 3a70a1912415 |
12 | 163484a45031 |
13 | 8299621a932 |
14 | 3cb0add37c9 |
15 | 1e6a61a9dad |
hex | 107913b9de5 |
1132013002213 has 2 divisors, whose sum is σ = 1132013002214. Its totient is φ = 1132013002212.
The previous prime is 1132013002201. The next prime is 1132013002249. The reversal of 1132013002213 is 3122003102311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1044528968484 + 87484033729 = 1022022^2 + 295777^2 .
It is a cyclic number.
It is not a de Polignac number, because 1132013002213 - 25 = 1132013002181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1138013002213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566006501106 + 566006501107.
It is an arithmetic number, because the mean of its divisors is an integer number (566006501107).
Almost surely, 21132013002213 is an apocalyptic number.
It is an amenable number.
1132013002213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132013002213 is an equidigital number, since it uses as much as digits as its factorization.
1132013002213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1132013002213 its reverse (3122003102311), we get a palindrome (4254016104524).
The spelling of 1132013002213 in words is "one trillion, one hundred thirty-two billion, thirteen million, two thousand, two hundred thirteen".
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