Base | Representation |
---|---|
bin | 11001101111010010111101… |
… | …110010101001001100100110 |
3 | 112211210221110011201202001211 |
4 | 121233102331302221030212 |
5 | 104314142322102120032 |
6 | 1040431551221542034 |
7 | 32562345534445645 |
oct | 3157227562511446 |
9 | 484727404652054 |
10 | 113201342223142 |
11 | 33084468594198 |
12 | 1084321857491a |
13 | 4b21ac121cbb4 |
14 | 1dd4d8d2ab35c |
15 | d1496015b747 |
hex | 66f4bdca9326 |
113201342223142 has 4 divisors (see below), whose sum is σ = 169802013334716. Its totient is φ = 56600671111570.
The previous prime is 113201342223131. The next prime is 113201342223181. The reversal of 113201342223142 is 241322243102311.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1132013422231422 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28300335555784 + ... + 28300335555787.
It is an arithmetic number, because the mean of its divisors is an integer number (42450503333679).
Almost surely, 2113201342223142 is an apocalyptic number.
113201342223142 is a deficient number, since it is larger than the sum of its proper divisors (56600671111574).
113201342223142 is an equidigital number, since it uses as much as digits as its factorization.
113201342223142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56600671111573.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 113201342223142 its reverse (241322243102311), we get a palindrome (354523585325453).
The spelling of 113201342223142 in words is "one hundred thirteen trillion, two hundred one billion, three hundred forty-two million, two hundred twenty-three thousand, one hundred forty-two".
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