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1132014132241 = 3136516584911
BaseRepresentation
bin10000011110010001010…
…011001101110000010001
311000012221000022012010021
4100132101103031300101
5122021331104212431
62224012355303441
7144533236235026
oct20362123156021
94005830265107
101132014132241
113a70a2514423
121634852aab81
13829965250a5
143cb0b20954d
151e6a632eb11
hex107914cdc11

1132014132241 has 4 divisors (see below), whose sum is σ = 1168530717184. Its totient is φ = 1095497547300.

The previous prime is 1132014132209. The next prime is 1132014132259. The reversal of 1132014132241 is 1422314102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1132014132241 - 25 = 1132014132209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1132014132341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18258292425 + ... + 18258292486.

It is an arithmetic number, because the mean of its divisors is an integer number (292132679296).

Almost surely, 21132014132241 is an apocalyptic number.

It is an amenable number.

1132014132241 is a deficient number, since it is larger than the sum of its proper divisors (36516584943).

1132014132241 is an equidigital number, since it uses as much as digits as its factorization.

1132014132241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36516584942.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1132014132241 its reverse (1422314102311), we get a palindrome (2554328234552).

The spelling of 1132014132241 in words is "one trillion, one hundred thirty-two billion, fourteen million, one hundred thirty-two thousand, two hundred forty-one".

Divisors: 1 31 36516584911 1132014132241