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113201454703 is a prime number
BaseRepresentation
bin110100101101101010…
…1010001111001101111
3101211012012111201121111
41221123111101321233
53323314033022303
6124000512012451
711115144326431
oct1513325217157
9354165451544
10113201454703
11440102a7447
1219b32b31127
13a8a08578bc
14569c46a651
152e281d1b6d
hex1a5b551e6f

113201454703 has 2 divisors, whose sum is σ = 113201454704. Its totient is φ = 113201454702.

The previous prime is 113201454697. The next prime is 113201454713. The reversal of 113201454703 is 307454102311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113201454703 - 229 = 112664583791 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113201454713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600727351 + 56600727352.

It is an arithmetic number, because the mean of its divisors is an integer number (56600727352).

Almost surely, 2113201454703 is an apocalyptic number.

113201454703 is a deficient number, since it is larger than the sum of its proper divisors (1).

113201454703 is an equidigital number, since it uses as much as digits as its factorization.

113201454703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 113201454703 in words is "one hundred thirteen billion, two hundred one million, four hundred fifty-four thousand, seven hundred three".