Base | Representation |
---|---|
bin | 110100101101101011… |
… | …1011100111011001100 |
3 | 101211012020120122201202 |
4 | 1221123113130323030 |
5 | 3323314204233030 |
6 | 124000532125032 |
7 | 11115152220542 |
oct | 1513327347314 |
9 | 354166518652 |
10 | 113202024140 |
11 | 44010656257 |
12 | 19b33166778 |
13 | a8a09c6b4a |
14 | 569c577d92 |
15 | 2e28295745 |
hex | 1a5b5dcecc |
113202024140 has 12 divisors (see below), whose sum is σ = 237724250736. Its totient is φ = 45280809648.
The previous prime is 113202024127. The next prime is 113202024161. The reversal of 113202024140 is 41420202311.
It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 5660101207 = 113202024140 / (1 + 1 + 3 + 2 + 0 + 2 + 0 + 2 + 4 + 1 + 4 + 0).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2830050584 + ... + 2830050623.
It is an arithmetic number, because the mean of its divisors is an integer number (19810354228).
Almost surely, 2113202024140 is an apocalyptic number.
113202024140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113202024140 is an abundant number, since it is smaller than the sum of its proper divisors (124522226596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113202024140 is a wasteful number, since it uses less digits than its factorization.
113202024140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5660101216 (or 5660101214 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 113202024140 its reverse (41420202311), we get a palindrome (154622226451).
The spelling of 113202024140 in words is "one hundred thirteen billion, two hundred two million, twenty-four thousand, one hundred forty".
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