11320302112121 has 4 divisors (see below), whose sum is σ = 11360587885044. Its totient is φ = 11280016339200.

The previous prime is 11320302112111. The next prime is 11320302112123. The reversal of 11320302112121 is 12121120302311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9041062730896 + 2279239381225 = 3006836^2 + 1509715^2 .

It is a cyclic number.

It is not a de Polignac number, because 11320302112121 - 2³⁸ = 11045424205177 is a prime.

It is a super-3 number, since 3×11320302112121³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11320302112093 and 11320302112102.

It is not an unprimeable number, because it can be changed into a prime (11320302112123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20142886040 + ... + 20142886601.

It is an arithmetic number, because the mean of its divisors is an integer number (2840146971261).

Almost surely, 2^{11320302112121} is an apocalyptic number.

It is an amenable number.

11320302112121 is a deficient number, since it is larger than the sum of its proper divisors (40285772923).

11320302112121 is an equidigital number, since it uses as much as digits as its factorization.

11320302112121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40285772922.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11320302112121 its reverse (12121120302311), we get a palindrome (23441422414432).

The spelling of 11320302112121 in words is "eleven trillion, three hundred twenty billion, three hundred two million, one hundred twelve thousand, one hundred twenty-one".