Base | Representation |
---|---|
bin | 110100101101101110… |
… | …0001000011101100111 |
3 | 101211012022212222201202 |
4 | 1221123130020131213 |
5 | 3323320013013142 |
6 | 124001014313115 |
7 | 11115165520535 |
oct | 1513334103547 |
9 | 354168788652 |
10 | 113203251047 |
11 | 44011314027 |
12 | 19b3365879b |
13 | a8a1036423 |
14 | 569c7b7155 |
15 | 2e28439032 |
hex | 1a5b708767 |
113203251047 has 2 divisors, whose sum is σ = 113203251048. Its totient is φ = 113203251046.
The previous prime is 113203251043. The next prime is 113203251067. The reversal of 113203251047 is 740152302311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113203251047 - 22 = 113203251043 is a prime.
It is a super-4 number, since 4×1132032510474 (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113203251043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56601625523 + 56601625524.
It is an arithmetic number, because the mean of its divisors is an integer number (56601625524).
Almost surely, 2113203251047 is an apocalyptic number.
113203251047 is a deficient number, since it is larger than the sum of its proper divisors (1).
113203251047 is an equidigital number, since it uses as much as digits as its factorization.
113203251047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 113203251047 its reverse (740152302311), we get a palindrome (853355553358).
The spelling of 113203251047 in words is "one hundred thirteen billion, two hundred three million, two hundred fifty-one thousand, forty-seven".
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