Base | Representation |
---|---|
bin | 1010010010111110000111… |
… | …1110001011110110110011 |
3 | 1111002021120001020101202022 |
4 | 2210233201332023312303 |
5 | 2440440432140000201 |
6 | 40024450454342055 |
7 | 2245626451152332 |
oct | 244574176136663 |
9 | 44067501211668 |
10 | 11321030000051 |
11 | 3675249329542 |
12 | 132a11205a92b |
13 | 64175113c775 |
14 | 2b1d256b9d19 |
15 | 14974523e41b |
hex | a4be1f8bdb3 |
11321030000051 has 2 divisors, whose sum is σ = 11321030000052. Its totient is φ = 11321030000050.
The previous prime is 11321030000039. The next prime is 11321030000069. The reversal of 11321030000051 is 15000003012311.
It is a weak prime.
It is an emirp because it is prime and its reverse (15000003012311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11321030000051 - 26 = 11321029999987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11321029999984 and 11321030000029.
It is not a weakly prime, because it can be changed into another prime (11321030000551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660515000025 + 5660515000026.
It is an arithmetic number, because the mean of its divisors is an integer number (5660515000026).
Almost surely, 211321030000051 is an apocalyptic number.
11321030000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11321030000051 is an equidigital number, since it uses as much as digits as its factorization.
11321030000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 11321030000051 its reverse (15000003012311), we get a palindrome (26321033012362).
The spelling of 11321030000051 in words is "eleven trillion, three hundred twenty-one billion, thirty million, fifty-one", and thus it is an aban number.
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