Base | Representation |
---|---|
bin | 1010010010111110100010… |
… | …0110011001010111011111 |
3 | 1111002021211210111011111122 |
4 | 2210233220212121113133 |
5 | 2440441144122020242 |
6 | 40024505510041155 |
7 | 2245632301321364 |
oct | 244575046312737 |
9 | 44067753434448 |
10 | 11321141204447 |
11 | 36752a6082aa8 |
12 | 132a1433491bb |
13 | 64176b1a7099 |
14 | 2b1d3638646b |
15 | 14974eda8ad2 |
hex | a4be89995df |
11321141204447 has 2 divisors, whose sum is σ = 11321141204448. Its totient is φ = 11321141204446.
The previous prime is 11321141204423. The next prime is 11321141204479. The reversal of 11321141204447 is 74440214112311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11321141204447 - 210 = 11321141203423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11321141206447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660570602223 + 5660570602224.
It is an arithmetic number, because the mean of its divisors is an integer number (5660570602224).
Almost surely, 211321141204447 is an apocalyptic number.
11321141204447 is a deficient number, since it is larger than the sum of its proper divisors (1).
11321141204447 is an equidigital number, since it uses as much as digits as its factorization.
11321141204447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 11321141204447 its reverse (74440214112311), we get a palindrome (85761355316758).
The spelling of 11321141204447 in words is "eleven trillion, three hundred twenty-one billion, one hundred forty-one million, two hundred four thousand, four hundred forty-seven".
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