Base | Representation |
---|---|
bin | 1010010010111110110011… |
… | …1000101001111111110011 |
3 | 1111002022000210202211200121 |
4 | 2210233230320221333303 |
5 | 2440441321023200034 |
6 | 40024520555031111 |
7 | 2245634133401434 |
oct | 244575470517763 |
9 | 44068023684617 |
10 | 11321213100019 |
11 | 3675332719229 |
12 | 132a16343b497 |
13 | 64178005a644 |
14 | 2b1d41b3d48b |
15 | 14975635b1b4 |
hex | a4bece29ff3 |
11321213100019 has 2 divisors, whose sum is σ = 11321213100020. Its totient is φ = 11321213100018.
The previous prime is 11321213100013. The next prime is 11321213100053. The reversal of 11321213100019 is 91000131212311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11321213100019 - 221 = 11321211002867 is a prime.
It is a super-2 number, since 2×113212131000192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11321213099966 and 11321213100002.
It is not a weakly prime, because it can be changed into another prime (11321213100013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660606550009 + 5660606550010.
It is an arithmetic number, because the mean of its divisors is an integer number (5660606550010).
Almost surely, 211321213100019 is an apocalyptic number.
11321213100019 is a deficient number, since it is larger than the sum of its proper divisors (1).
11321213100019 is an equidigital number, since it uses as much as digits as its factorization.
11321213100019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 11321213100019 in words is "eleven trillion, three hundred twenty-one billion, two hundred thirteen million, one hundred thousand, nineteen".
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