Base | Representation |
---|---|
bin | 10000011110010111101… |
… | …110101111010111101001 |
3 | 11000020012112022000010001 |
4 | 100132113232233113221 |
5 | 122022041213323423 |
6 | 2224031211423001 |
7 | 144536016213502 |
oct | 20362756572751 |
9 | 4006175260101 |
10 | 1132122011113 |
11 | 3a71483a7415 |
12 | 1634b5454a61 |
13 | 829b2996b42 |
14 | 3cb1b68bba9 |
15 | 1e6b0a3dcad |
hex | 10797baf5e9 |
1132122011113 has 2 divisors, whose sum is σ = 1132122011114. Its totient is φ = 1132122011112.
The previous prime is 1132122011099. The next prime is 1132122011159. The reversal of 1132122011113 is 3111102212311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1061707673664 + 70414337449 = 1030392^2 + 265357^2 .
It is a cyclic number.
It is not a de Polignac number, because 1132122011113 - 25 = 1132122011081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1132122011183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566061005556 + 566061005557.
It is an arithmetic number, because the mean of its divisors is an integer number (566061005557).
Almost surely, 21132122011113 is an apocalyptic number.
It is an amenable number.
1132122011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132122011113 is an equidigital number, since it uses as much as digits as its factorization.
1132122011113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1132122011113 its reverse (3111102212311), we get a palindrome (4243224223424).
The spelling of 1132122011113 in words is "one trillion, one hundred thirty-two billion, one hundred twenty-two million, eleven thousand, one hundred thirteen".
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