Base | Representation |
---|---|
bin | 11001101111011101110100… |
… | …101101011011001010001111 |
3 | 112211212001112200210222202121 |
4 | 121233131310231123022033 |
5 | 104314340211230120142 |
6 | 1040441200142233411 |
7 | 32563240463544325 |
oct | 3157356455331217 |
9 | 484761480728677 |
10 | 113213001020047 |
11 | 33089400689935 |
12 | 10845530b85867 |
13 | 4b22c2b78b5a6 |
14 | 1dd577786bd15 |
15 | d14de397ec67 |
hex | 66f774b5b28f |
113213001020047 has 2 divisors, whose sum is σ = 113213001020048. Its totient is φ = 113213001020046.
The previous prime is 113213001019997. The next prime is 113213001020107. The reversal of 113213001020047 is 740020100312311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113213001020047 - 211 = 113213001017999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113213001021047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56606500510023 + 56606500510024.
It is an arithmetic number, because the mean of its divisors is an integer number (56606500510024).
Almost surely, 2113213001020047 is an apocalyptic number.
113213001020047 is a deficient number, since it is larger than the sum of its proper divisors (1).
113213001020047 is an equidigital number, since it uses as much as digits as its factorization.
113213001020047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 113213001020047 its reverse (740020100312311), we get a palindrome (853233101332358).
The spelling of 113213001020047 in words is "one hundred thirteen trillion, two hundred thirteen billion, one million, twenty thousand, forty-seven".
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