Base | Representation |
---|---|
bin | 1010010010111111001011… |
… | …0110111100100010111111 |
3 | 1111002022021210100021210211 |
4 | 2210233302312330202333 |
5 | 2440442022202040012 |
6 | 40024534535013251 |
7 | 2245636461250423 |
oct | 244576266744277 |
9 | 44068253307724 |
10 | 11321313315007 |
11 | 3675384247233 |
12 | 132a190b0a227 |
13 | 641797a47c57 |
14 | 2b1d51188b83 |
15 | 1497600546a7 |
hex | a4bf2dbc8bf |
11321313315007 has 2 divisors, whose sum is σ = 11321313315008. Its totient is φ = 11321313315006.
The previous prime is 11321313314989. The next prime is 11321313315043. The reversal of 11321313315007 is 70051331312311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11321313315007 - 219 = 11321312790719 is a prime.
It is a super-2 number, since 2×113213133150072 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11321313315007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11321313312007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660656657503 + 5660656657504.
It is an arithmetic number, because the mean of its divisors is an integer number (5660656657504).
Almost surely, 211321313315007 is an apocalyptic number.
11321313315007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11321313315007 is an equidigital number, since it uses as much as digits as its factorization.
11321313315007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5670, while the sum is 31.
Adding to 11321313315007 its reverse (70051331312311), we get a palindrome (81372644627318).
The spelling of 11321313315007 in words is "eleven trillion, three hundred twenty-one billion, three hundred thirteen million, three hundred fifteen thousand, seven".
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