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11321313315007 is a prime number
BaseRepresentation
bin1010010010111111001011…
…0110111100100010111111
31111002022021210100021210211
42210233302312330202333
52440442022202040012
640024534535013251
72245636461250423
oct244576266744277
944068253307724
1011321313315007
113675384247233
12132a190b0a227
13641797a47c57
142b1d51188b83
151497600546a7
hexa4bf2dbc8bf

11321313315007 has 2 divisors, whose sum is σ = 11321313315008. Its totient is φ = 11321313315006.

The previous prime is 11321313314989. The next prime is 11321313315043. The reversal of 11321313315007 is 70051331312311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11321313315007 - 219 = 11321312790719 is a prime.

It is a super-2 number, since 2×113213133150072 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11321313315007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11321313312007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660656657503 + 5660656657504.

It is an arithmetic number, because the mean of its divisors is an integer number (5660656657504).

Almost surely, 211321313315007 is an apocalyptic number.

11321313315007 is a deficient number, since it is larger than the sum of its proper divisors (1).

11321313315007 is an equidigital number, since it uses as much as digits as its factorization.

11321313315007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5670, while the sum is 31.

Adding to 11321313315007 its reverse (70051331312311), we get a palindrome (81372644627318).

The spelling of 11321313315007 in words is "eleven trillion, three hundred twenty-one billion, three hundred thirteen million, three hundred fifteen thousand, seven".