Base | Representation |
---|---|
bin | 110100101110000001… |
… | …0100000100001001011 |
3 | 101211020000211002110111 |
4 | 1221130002200201023 |
5 | 3323330101423201 |
6 | 124002014055151 |
7 | 11115350160151 |
oct | 1513402404113 |
9 | 354200732414 |
10 | 113213311051 |
11 | 44016a65285 |
12 | 19b36aaa4b7 |
13 | a8a31493a9 |
14 | 569dc753d1 |
15 | 2e29274b51 |
hex | 1a5c0a084b |
113213311051 has 2 divisors, whose sum is σ = 113213311052. Its totient is φ = 113213311050.
The previous prime is 113213311019. The next prime is 113213311063. The reversal of 113213311051 is 150113312311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113213311051 - 25 = 113213311019 is a prime.
It is not a weakly prime, because it can be changed into another prime (113213311451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56606655525 + 56606655526.
It is an arithmetic number, because the mean of its divisors is an integer number (56606655526).
Almost surely, 2113213311051 is an apocalyptic number.
113213311051 is a deficient number, since it is larger than the sum of its proper divisors (1).
113213311051 is an equidigital number, since it uses as much as digits as its factorization.
113213311051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 22.
Adding to 113213311051 its reverse (150113312311), we get a palindrome (263326623362).
The spelling of 113213311051 in words is "one hundred thirteen billion, two hundred thirteen million, three hundred eleven thousand, fifty-one".
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