Base | Representation |
---|---|
bin | 110100101110000001… |
… | …0111001000001010101 |
3 | 101211020001000012010121 |
4 | 1221130002321001111 |
5 | 3323330113131123 |
6 | 124002020151541 |
7 | 11115351055564 |
oct | 1513402710125 |
9 | 354201005117 |
10 | 113213411413 |
11 | 44017023723 |
12 | 19b36b385b1 |
13 | a8a3182c8b |
14 | 569dc9dbdb |
15 | 2e2929475d |
hex | 1a5c0b9055 |
113213411413 has 4 divisors (see below), whose sum is σ = 113238874240. Its totient is φ = 113187948588.
The previous prime is 113213411401. The next prime is 113213411453. The reversal of 113213411413 is 314114312311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 314114312311 = 250253 ⋅1255187.
It is a cyclic number.
It is not a de Polignac number, because 113213411413 - 29 = 113213410901 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113213411453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12724743 + ... + 12733636.
It is an arithmetic number, because the mean of its divisors is an integer number (28309718560).
Almost surely, 2113213411413 is an apocalyptic number.
It is an amenable number.
113213411413 is a deficient number, since it is larger than the sum of its proper divisors (25462827).
113213411413 is an equidigital number, since it uses as much as digits as its factorization.
113213411413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25462826.
The product of its digits is 864, while the sum is 25.
Adding to 113213411413 its reverse (314114312311), we get a palindrome (427327723724).
The spelling of 113213411413 in words is "one hundred thirteen billion, two hundred thirteen million, four hundred eleven thousand, four hundred thirteen".
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