Base | Representation |
---|---|
bin | 10101000101101100… |
… | …00011010101101001 |
3 | 1002020001100212002001 |
4 | 22202312003111221 |
5 | 141141413404113 |
6 | 5111250011001 |
7 | 550366344232 |
oct | 124266032551 |
9 | 32201325061 |
10 | 11322013033 |
11 | 488aa87a71 |
12 | 223b876a61 |
13 | 10b5861bc6 |
14 | 795974089 |
15 | 463e9a7dd |
hex | 2a2d83569 |
11322013033 has 2 divisors, whose sum is σ = 11322013034. Its totient is φ = 11322013032.
The previous prime is 11322013013. The next prime is 11322013049. The reversal of 11322013033 is 33031022311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9100587609 + 2221425424 = 95397^2 + 47132^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11322013033 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11322013033.
It is not a weakly prime, because it can be changed into another prime (11322013013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661006516 + 5661006517.
It is an arithmetic number, because the mean of its divisors is an integer number (5661006517).
Almost surely, 211322013033 is an apocalyptic number.
It is an amenable number.
11322013033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322013033 is an equidigital number, since it uses as much as digits as its factorization.
11322013033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 11322013033 its reverse (33031022311), we get a palindrome (44353035344).
It can be divided in two parts, 113220 and 13033, that added together give a triangular number (126253 = T502).
The spelling of 11322013033 in words is "eleven billion, three hundred twenty-two million, thirteen thousand, thirty-three".
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