Base | Representation |
---|---|
bin | 10101000101101100… |
… | …01010101110101110 |
3 | 1002020001102101121102 |
4 | 22202312022232232 |
5 | 141141420341220 |
6 | 5111250403102 |
7 | 550366531424 |
oct | 124266125656 |
9 | 32201371542 |
10 | 11322043310 |
11 | 488aaa8796 |
12 | 223b890492 |
13 | 10b5872916 |
14 | 795981114 |
15 | 463ea4775 |
hex | 2a2d8abae |
11322043310 has 32 divisors (see below), whose sum is σ = 20501208000. Its totient is φ = 4501854720.
The previous prime is 11322043309. The next prime is 11322043331. The reversal of 11322043310 is 1334022311.
It is a super-2 number, since 2×113220433102 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2961200 + ... + 2965020.
It is an arithmetic number, because the mean of its divisors is an integer number (640662750).
Almost surely, 211322043310 is an apocalyptic number.
11322043310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11322043310 is a deficient number, since it is larger than the sum of its proper divisors (9179164690).
11322043310 is a wasteful number, since it uses less digits than its factorization.
11322043310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5516.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11322043310 its reverse (1334022311), we get a palindrome (12656065621).
The spelling of 11322043310 in words is "eleven billion, three hundred twenty-two million, forty-three thousand, three hundred ten".
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