Base | Representation |
---|---|
bin | 1010010011000010000111… |
… | …0000101110000100100011 |
3 | 1111002101022122000210120000 |
4 | 2210300201300232010203 |
5 | 2441000130123241003 |
6 | 40025145004551043 |
7 | 2245665124621650 |
oct | 244604160560443 |
9 | 44071278023500 |
10 | 11322100212003 |
11 | 3675748448629 |
12 | 132a370552483 |
13 | 641891a90a89 |
14 | 2b1dc78a2c27 |
15 | 1497a918e1a3 |
hex | a4c21c2e123 |
11322100212003 has 40 divisors (see below), whose sum is σ = 19332407798880. Its totient is φ = 6468778506240.
The previous prime is 11322100212001. The next prime is 11322100212023. The reversal of 11322100212003 is 30021200122311.
It is not a de Polignac number, because 11322100212003 - 21 = 11322100212001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11322100212001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2172733 + ... + 5231153.
It is an arithmetic number, because the mean of its divisors is an integer number (483310194972).
Almost surely, 211322100212003 is an apocalyptic number.
11322100212003 is a deficient number, since it is larger than the sum of its proper divisors (8010307586877).
11322100212003 is an equidigital number, since it uses as much as digits as its factorization.
11322100212003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3064969 (or 3064960 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 11322100212003 its reverse (30021200122311), we get a palindrome (41343300334314).
The spelling of 11322100212003 in words is "eleven trillion, three hundred twenty-two billion, one hundred million, two hundred twelve thousand, three".
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