Base | Representation |
---|---|
bin | 1010010011000010001011… |
… | …1101000101100011101111 |
3 | 1111002101101000200212122221 |
4 | 2210300202331011203233 |
5 | 2441000200234344101 |
6 | 40025151002020211 |
7 | 2245665460030552 |
oct | 244604275054357 |
9 | 44071330625587 |
10 | 11322120231151 |
11 | 3675758781284 |
12 | 132a3771a7667 |
13 | 641895c7cb22 |
14 | 2b1dca3d4699 |
15 | 1497aace5aa1 |
hex | a4c22f458ef |
11322120231151 has 2 divisors, whose sum is σ = 11322120231152. Its totient is φ = 11322120231150.
The previous prime is 11322120231131. The next prime is 11322120231179. The reversal of 11322120231151 is 15113202122311.
11322120231151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11322120231151 - 29 = 11322120230639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11322120231131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661060115575 + 5661060115576.
It is an arithmetic number, because the mean of its divisors is an integer number (5661060115576).
Almost surely, 211322120231151 is an apocalyptic number.
11322120231151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322120231151 is an equidigital number, since it uses as much as digits as its factorization.
11322120231151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 11322120231151 its reverse (15113202122311), we get a palindrome (26435322353462).
The spelling of 11322120231151 in words is "eleven trillion, three hundred twenty-two billion, one hundred twenty million, two hundred thirty-one thousand, one hundred fifty-one".
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