1132214513433 has 4 divisors (see below), whose sum is σ = 1509619351248. Its totient is φ = 754809675620.

The previous prime is 1132214513429. The next prime is 1132214513447. The reversal of 1132214513433 is 3343154122311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1132214513433 - 2² = 1132214513429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1132214513394 and 1132214513403.

It is not an unprimeable number, because it can be changed into a prime (1132214513033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188702418903 + ... + 188702418908.

It is an arithmetic number, because the mean of its divisors is an integer number (377404837812).

Almost surely, 2^{1132214513433} is an apocalyptic number.

It is an amenable number.

1132214513433 is a deficient number, since it is larger than the sum of its proper divisors (377404837815).

1132214513433 is an equidigital number, since it uses as much as digits as its factorization.

1132214513433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377404837814.

The product of its digits is 25920, while the sum is 33.

Adding to 1132214513433 its reverse (3343154122311), we get a palindrome (4475368635744).

The spelling of 1132214513433 in words is "one trillion, one hundred thirty-two billion, two hundred fourteen million, five hundred thirteen thousand, four hundred thirty-three".