Base | Representation |
---|---|
bin | 110100101110010001… |
… | …1101100101000101001 |
3 | 101211020122012010010212 |
4 | 1221130203230220221 |
5 | 3323334313331213 |
6 | 124002524350505 |
7 | 11115514134536 |
oct | 1513443545051 |
9 | 354218163125 |
10 | 113222011433 |
11 | 44020967a83 |
12 | 19b399a5435 |
13 | a8a4ba454b |
14 | 56a109bd8d |
15 | 2e29de29a8 |
hex | 1a5c8eca29 |
113222011433 has 2 divisors, whose sum is σ = 113222011434. Its totient is φ = 113222011432.
The previous prime is 113222011429. The next prime is 113222011453. The reversal of 113222011433 is 334110222311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101004467344 + 12217544089 = 317812^2 + 110533^2 .
It is a cyclic number.
It is not a de Polignac number, because 113222011433 - 22 = 113222011429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113222011399 and 113222011408.
It is not a weakly prime, because it can be changed into another prime (113222011453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56611005716 + 56611005717.
It is an arithmetic number, because the mean of its divisors is an integer number (56611005717).
Almost surely, 2113222011433 is an apocalyptic number.
It is an amenable number.
113222011433 is a deficient number, since it is larger than the sum of its proper divisors (1).
113222011433 is an equidigital number, since it uses as much as digits as its factorization.
113222011433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 113222011433 its reverse (334110222311), we get a palindrome (447332233744).
The spelling of 113222011433 in words is "one hundred thirteen billion, two hundred twenty-two million, eleven thousand, four hundred thirty-three".
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