Base | Representation |
---|---|
bin | 1010010011000010011111… |
… | …0101011001000101001111 |
3 | 1111002101120201202020200021 |
4 | 2210300213311121011033 |
5 | 2441000332214200142 |
6 | 40025203044443011 |
7 | 2246000502636436 |
oct | 244604765310517 |
9 | 44071521666607 |
10 | 11322202100047 |
11 | 367579aa09623 |
12 | 132a39a6a9467 |
13 | 6418a9c15a67 |
14 | 2b1dd722611d |
15 | 1497b30b8267 |
hex | a4c27d5914f |
11322202100047 has 2 divisors, whose sum is σ = 11322202100048. Its totient is φ = 11322202100046.
The previous prime is 11322202100023. The next prime is 11322202100101. The reversal of 11322202100047 is 74000120222311.
11322202100047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11322202100047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11322202099994 and 11322202100030.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11322202100347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661101050023 + 5661101050024.
It is an arithmetic number, because the mean of its divisors is an integer number (5661101050024).
Almost surely, 211322202100047 is an apocalyptic number.
11322202100047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322202100047 is an equidigital number, since it uses as much as digits as its factorization.
11322202100047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 11322202100047 its reverse (74000120222311), we get a palindrome (85322322322358).
The spelling of 11322202100047 in words is "eleven trillion, three hundred twenty-two billion, two hundred two million, one hundred thousand, forty-seven".
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