Base | Representation |
---|---|
bin | 10000011110011110010… |
… | …010110010001011101001 |
3 | 11000020111012111021101021 |
4 | 100132132102302023221 |
5 | 122022302410414423 |
6 | 2224050143452441 |
7 | 144541524152650 |
oct | 20363622621351 |
9 | 4006435437337 |
10 | 1132232123113 |
11 | 3a71a4575173 |
12 | 1635262b7121 |
13 | 829cc73b180 |
14 | 3cb2c152197 |
15 | 1e6ba53e95d |
hex | 1079e4b22e9 |
1132232123113 has 8 divisors (see below), whose sum is σ = 1393516459328. Its totient is φ = 895832009424.
The previous prime is 1132232123093. The next prime is 1132232123129. The reversal of 1132232123113 is 3113212322311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1132232123113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1132232123173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6221055531 + ... + 6221055712.
It is an arithmetic number, because the mean of its divisors is an integer number (174189557416).
Almost surely, 21132232123113 is an apocalyptic number.
1132232123113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1132232123113 is a deficient number, since it is larger than the sum of its proper divisors (261284336215).
1132232123113 is a wasteful number, since it uses less digits than its factorization.
1132232123113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12442111263.
The product of its digits is 1296, while the sum is 25.
Adding to 1132232123113 its reverse (3113212322311), we get a palindrome (4245444445424).
The spelling of 1132232123113 in words is "one trillion, one hundred thirty-two billion, two hundred thirty-two million, one hundred twenty-three thousand, one hundred thirteen".
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