Base | Representation |
---|---|
bin | 1010010011000101011110… |
… | …0100100111110100000111 |
3 | 1111002110122112210201000101 |
4 | 2210301113210213310013 |
5 | 2441004002232312221 |
6 | 40025414335024531 |
7 | 2246026366363666 |
oct | 244612744476407 |
9 | 44073575721011 |
10 | 11323003010311 |
11 | 3676071011333 |
12 | 132a58296b147 |
13 | 6419a6b27065 |
14 | 2b207174addd |
15 | 14980d56ed91 |
hex | a4c57927d07 |
11323003010311 has 2 divisors, whose sum is σ = 11323003010312. Its totient is φ = 11323003010310.
The previous prime is 11323003010257. The next prime is 11323003010381. The reversal of 11323003010311 is 11301030032311.
11323003010311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11323003010311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11323003010381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661501505155 + 5661501505156.
It is an arithmetic number, because the mean of its divisors is an integer number (5661501505156).
Almost surely, 211323003010311 is an apocalyptic number.
11323003010311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323003010311 is an equidigital number, since it uses as much as digits as its factorization.
11323003010311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11323003010311 its reverse (11301030032311), we get a palindrome (22624033042622).
The spelling of 11323003010311 in words is "eleven trillion, three hundred twenty-three billion, three million, ten thousand, three hundred eleven".
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