Base | Representation |
---|---|
bin | 10101000101110011… |
… | …10111000011110111 |
3 | 1002020010020120110121 |
4 | 22202321313003313 |
5 | 141142142330234 |
6 | 5111323232411 |
7 | 550411002544 |
oct | 124271670367 |
9 | 32203216417 |
10 | 11323011319 |
11 | 48905a9aa4 |
12 | 2240078707 |
13 | 10b5b213c9 |
14 | 795b53bcb |
15 | 4640e64b4 |
hex | 2a2e770f7 |
11323011319 has 4 divisors (see below), whose sum is σ = 11536653096. Its totient is φ = 11109369544.
The previous prime is 11323011277. The next prime is 11323011341. The reversal of 11323011319 is 91311032311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 91311032311 = 131 ⋅697030781.
It is a cyclic number.
It is not a de Polignac number, because 11323011319 - 215 = 11322978551 is a prime.
It is a super-2 number, since 2×113230113192 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11323011293 and 11323011302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11323011419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106820809 + ... + 106820914.
It is an arithmetic number, because the mean of its divisors is an integer number (2884163274).
Almost surely, 211323011319 is an apocalyptic number.
11323011319 is a deficient number, since it is larger than the sum of its proper divisors (213641777).
11323011319 is an equidigital number, since it uses as much as digits as its factorization.
11323011319 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213641776.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 11323011319 in words is "eleven billion, three hundred twenty-three million, eleven thousand, three hundred nineteen".
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