Base | Representation |
---|---|
bin | 10000011110100010011… |
… | …101011101110001101101 |
3 | 11000020200002001000022121 |
4 | 100132202131131301231 |
5 | 122022423310010411 |
6 | 2224101122112541 |
7 | 144543333316621 |
oct | 20364235356155 |
9 | 4006602030277 |
10 | 1132302031981 |
11 | 3a722aa8379a |
12 | 1635457ab751 |
13 | 82a11077373 |
14 | 3cb3754d181 |
15 | 1e6c174d571 |
hex | 107a275dc6d |
1132302031981 has 2 divisors, whose sum is σ = 1132302031982. Its totient is φ = 1132302031980.
The previous prime is 1132302031961. The next prime is 1132302032003. The reversal of 1132302031981 is 1891302032311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1124882966025 + 7419065956 = 1060605^2 + 86134^2 .
It is a cyclic number.
It is not a de Polignac number, because 1132302031981 - 27 = 1132302031853 is a prime.
It is a super-2 number, since 2×11323020319812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1132302031961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566151015990 + 566151015991.
It is an arithmetic number, because the mean of its divisors is an integer number (566151015991).
Almost surely, 21132302031981 is an apocalyptic number.
It is an amenable number.
1132302031981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132302031981 is an equidigital number, since it uses as much as digits as its factorization.
1132302031981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 34.
The spelling of 1132302031981 in words is "one trillion, one hundred thirty-two billion, three hundred two million, thirty-one thousand, nine hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •