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1132303101301 = 3600893144509
BaseRepresentation
bin10000011110100010100…
…001100010110101110101
311000020200011001100011001
4100132202201202311311
5122022424043220201
62224101201043301
7144543345362311
oct20364241426565
94006604040131
101132303101301
113a7230644129
12163546026531
1382a1135ccb8
143cb3774ab41
151e6c18b0301
hex107a2862d75

1132303101301 has 4 divisors (see below), whose sum is σ = 1132306605900. Its totient is φ = 1132299596704.

The previous prime is 1132303101289. The next prime is 1132303101313. The reversal of 1132303101301 is 1031013032311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1132303101289) and next prime (1132303101313).

It can be written as a sum of positive squares in 2 ways, for example, as 81452589201 + 1050850512100 = 285399^2 + 1025110^2 .

It is a cyclic number.

It is not a de Polignac number, because 1132303101301 - 27 = 1132303101173 is a prime.

It is a super-2 number, since 2×11323031013012 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1132303101701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1212166 + ... + 1932343.

It is an arithmetic number, because the mean of its divisors is an integer number (283076651475).

Almost surely, 21132303101301 is an apocalyptic number.

It is an amenable number.

1132303101301 is a deficient number, since it is larger than the sum of its proper divisors (3504599).

1132303101301 is an equidigital number, since it uses as much as digits as its factorization.

1132303101301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3504598.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1132303101301 its reverse (1031013032311), we get a palindrome (2163316133612).

The spelling of 1132303101301 in words is "one trillion, one hundred thirty-two billion, three hundred three million, one hundred one thousand, three hundred one".

Divisors: 1 360089 3144509 1132303101301